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135=1.2x+.04x^2
We move all terms to the left:
135-(1.2x+.04x^2)=0
We get rid of parentheses
-.04x^2-1.2x+135=0
We add all the numbers together, and all the variables
-0.04x^2-1.2x+135=0
a = -0.04; b = -1.2; c = +135;
Δ = b2-4ac
Δ = -1.22-4·(-0.04)·135
Δ = 23.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.2)-\sqrt{23.04}}{2*-0.04}=\frac{1.2-\sqrt{23.04}}{-0.08} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.2)+\sqrt{23.04}}{2*-0.04}=\frac{1.2+\sqrt{23.04}}{-0.08} $
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